Flutter Keyboard makes textfield hide

I'm new to flutter. I've added a form with a text field and when I clicked the textfield and keyboard comes, the textfield goes up.

This is my code :

Widget build(BuildContext context) {

MediaQueryData mediaQuery = MediaQuery.of(context);
return new Scaffold(
body: new Container(
color: Colors.purple,
constraints: new BoxConstraints.expand(),
padding: EdgeInsets.only(top: 10.0,left: 10.0,right: 10.0, bottom: mediaQuery.viewInsets.bottom, ),
child: SingleChildScrollView(
child: Container(
child: Column(
crossAxisAlignment: CrossAxisAlignment.center,
mainAxisAlignment: MainAxisAlignment.center,
children: <Widget>[
SizedBox(height: 12.0),
Text(
'What is your Bussiness Name?',
style: TextStyle(fontSize: 24.0),
),
AppForm(),
],
),
padding: EdgeInsets.only(left: 10.0,right: 10.0, bottom: mediaQuery.viewInsets.bottom),
decoration: BoxDecoration(
borderRadius: BorderRadius.all(Radius.circular(30.0)),
color: Colors.white,
),
)
)
),
);
}


This is the result without opening the keyboard:
Image without keyboard

This is the image after opening the keyboard:
Image after opening the keyboard



Here is my flutter doctor output.

Doctor summary (to see all details, run flutter doctor -v): [√] Flutter
(Channel beta, v0.5.1, on Microsoft Windows [Version 10.0.17134.165], locale
en-US) [√] Android toolchain - develop for Android devices (Android SDK
28.0.0) [√] Android Studio (version 3.1) [!] VS Code, 64-bit edition (version
1.25.1) [!] Connected devices ! No devices available ! Doctor found issues in
2 categories.


any idea how to fix this?

This was the case with me . You are definitely wrapping a scaffold inside another scaffold . there should be only one scaffold widget inside your flutter app i.e the main layout . Simple remove all the ancestor scaffolds you have and keep only one scaffold . dont wrap a scaffold into another scaffold .inspite of that you can wrap a scaffold inside a container .

Make sure in your main.dart file you are not doing this :-

✖✖

return Scaffold(
body : YourNewFileName(),
);


Inspite of the above code do this:-
✔✔

return YourNewFileName();